Answer:
0.9 = 90% probability that it arrived during the last 30 seconds of the 5-minute period.
Step-by-step explanation:
The car is equally as likely to arrive during each second of the interval, which means that the uniform distribution is used to solve this question.
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distribution has two bounds, a and b, and the probability of finding a value higher than x is given by:
[tex]P(X \geq x) = \frac{b - x}{b - a}[/tex]
5-minute period
This means that [tex]a = 0, b = 5*60 = 300[/tex]
Find the probability that it arrived during the last 30 seconds of the 5-minute period.
300 - 30 = 270. So
[tex]P(X \geq 270) = \frac{300 - 270}{300 - 0} = 0.9[/tex]
0.9 = 90% probability that it arrived during the last 30 seconds of the 5-minute period.
