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Superconducting cables conduct current with no resistance. Consequently, it is possible to pass huge currents through the cables, which, in turn, can produce very large forces. Two straight, parallel superconducting cables 4.5 mm apart (between centers) carry equal currents of 15000 A in opposite directions. Find the magnitude and direction of the force per unit length exerted by one conductor on the other. Should we be concerned about the mechanical strength of these wires

Respuesta :

Answer:

Explanation:

Force per unit length between two cables at distance d carrying current I₁ and I₂ can be given by the following expression .

F = 10⁻⁷ x 2I₁ I₂ / d

I₁ = I₂ = 15000 A

F = 10⁻⁷ x 2I₁ I₂ / d

= 10⁻⁷ x 2 x 15000² / 4.5 x 10⁻³ m

= 10000 N .

It will be repelling force ie they will repel each other because current is in opposite direction .

No , we should not be concerned about mechanical strength because force does not depend on it .

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