Respuesta :
Answer:
1. In 0.0250 moles of potassium chromate there are 0.05 moles of potassium , 0.025 moles of chromium and 0.1 moles of oxygen are present.
2. In 4.50 moles of ammonium carbonate there are 9 moles of ammonium ions and 4.5 moles of carbonate ions are present.
Explanation:
1.
Moles of potassium chromate = 0.0250 mol
Formula of potassium chromate = [tex]K_2CrO_4[/tex]
1 mole of potassium chromate has 2 moles of potassium , 1 mole of chromium and 4 moles of oxygen.
Then in 0.0250 moles of potassium chromate:
Moles of potassium will be:
[tex]2\times 0.0250 mol= 0.05 mol[/tex]
Moles of chromium will be:
[tex]1\times 0.0250 mol= 0.025 mol[/tex]
Moles of oxygen will be:
[tex]4\times 0.0250 mol= 0.1 mol[/tex]
2.
Moles of ammonium carbonate = 4.50 mol
Formula of ammonium carbonate =[tex](NH_4)_2CO_3[/tex]
1 mole of ammonium carbonate has 2 moles of ammonium ion and 1 mole of carbonate ion.
Then in 4.50 moles of ammonium carbonate:
Moles of ammonium ion will be:
[tex]2\times 4.50 mol= 9mol[/tex]
Moles of carbonate ions will be:
[tex]1\times 4.50 mol= 4.5 mol[/tex]
