Triangle D E F is shown. Angle D E F is 90 degrees and angle F D E is 42 degrees. The length of D E is 7.2 and the length of E F is d.
What is the value of d to the nearest hundredth?

Respuesta :

Answer:

The value of the d is 6.48

Step-by-step explanation:

The value of the d is 6.48, if the angle D E F is 90 degrees and angle F D E is 42 degrees and the length of D E is 7.2 and the length of E F is d.

Step-by-step explanation:

The given is,

                   Angle D E F is 90 degrees

                   Angle F D E is 42 degrees

                   The length of D E is 7.2

                   The length of E F is d

Step:1

                  For the given values,

                  Triangle DEF is right angle triangle,

                  Ref the attachment,

                            Angle FDE, ∅ = 42°

                                              DE = 7.2

                                              EF = d

                  Trigonometric ratio for the given right angle triangle,

                                            ∅ =  

                                            ∅ =  

                                         

                ( the value of tan 42° = 0.900404 )

                           

                                                 

                                        EF = d = 6.48

Result:

          The value of the d is 6.48, if the angle D E F is 90 degrees and angle F D E is 42 degrees and the length of D E is 7.2 and the length of E F is d.

Answer:

i just checked, the guy above me is correct : 6.48

Step-by-step explanation:

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