A paint manufacturer discovers that the mean volume of paint in a gallon-sized pail is 1 gallon with a standard deviation of 0.05 gallons. The paint volumes are approximately bell-shaped. Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.

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joaobezerra joaobezerra · Answer 1 · 2021-05-17T02:37:36+02:00

Answer:

Approximately 68%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 1, standard deviation = 0.05.

Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.

0.95 = 1 - 0.05

1.05 = 1 + 0.05

So within 1 standard deviation of the mean, which by the Empirical Rule, is approximately 68% of values.

raphealnwobi raphealnwobi · Answer 2 · 2021-12-10T11:56:32+01:00

68.29% of pails have volumes between 0.95 gallons and 1.05 gallons.

Z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

[tex]z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \sigma=standard\ deviation[/tex]

Given that:

μ = 1, σ = 0.05

[tex]For\ x=0.95:\\\\z=\frac{0.95-1}{0.05} =-1\\\\For\ x=1.05:\\\\z=\frac{1.05-1}{0.05} =1[/tex]

P(0.95 < x < 1.05) = P(-1 < z < 1) = P(z < 1) - P(z < -1) = 0.8413 - 0.1587 = 68.29%

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