Hi! Does anyone know the answer to this question? I’m bad at geometry and I’m struggling to get the answer. Please help!

Step-by-step explanation:
It is because of Angle-Angle Similarity.
Angle EDC = Angle CAB [Perpendicular, 90°]
Angle ECD = Angle ACB [Vertically Opposite Angles]
So,
Triangle ADC ~ Triangle BAC
Hope it helps :)
Answer:
Because of AA postulate
Step-by-step explanation:
[tex] In\: \triangle ABC\: \&\:\triangle DEC[/tex]
[tex] \angle CAB \cong \angle CDE[/tex] (Right angles)
[tex] \angle ACB \cong \angle DCE[/tex] (Vertical angles)
[tex] \therefore \triangle ABC \sim \triangle DEC[/tex] (AA postulate)