Respuesta :
The sixth term of an arithmetic sequence with fifth and common difference of 11 and 4 respectively is 15
Arithmetic sequence formula
aₙ = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
11 = a + 4d
d = 4
Hence,
11 = a + 4(4)
11 = a + 16
a = 11 - 16
a = -5
Therefore, the sixth term is as follows
a + 5d = a₆
-5 + 5(4) = a₆
a₆ = -5 + 20
a₆ = 15
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