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Given positive integer n, write a for loop that outputs the even numbers from n down to 0. If n is odd, start with the next lower even number. Hint: Use an if statement and the % operator to detect if n is odd, decrementing n if so. Enter an integer: 7 Sequence: 64 20 (2) If n is negative, output 0, Hint: Use an if statement to check if n is negative. If so, just set n = 0. Enter an integer: -1 Sequence: 0 Show transcribed image text (1) Given positive integer n, write a for loop that outputs the even numbers from n down to 0. If n is odd, start with the next lower even number. Hint: Use an if statement and the % operator to detect if n is odd, decrementing n if so. Enter an integer: 7 Sequence: 64 20 (2) If n is negative, output 0, Hint: Use an if statement to check if n is negative. If so, just set n = 0. Enter an integer: -1 Sequence: 0

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MrRoyal

Answer:

The program in Python is as follows:

n = int(input("Enter an integer: "))

if n < 0:

   n = 0

print("Sequence:",end=" ")

for i in range(n,-1,-1):

   if i%2 == 0:

       print(i,end = " ")

Explanation:

This gets input for n

n = int(input("Enter an integer: "))

This sets n to 0 if n is negative

if n < 0:

   n = 0

This prints the string "Sequence"

print("Sequence:",end=" ")

This iterates from n to 0

for i in range(n,-1,-1):

This check if current iteration value is even

   if i%2 == 0:

If yes, the number is printed

       print(i,end = " ")

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