Answer:
5.9 × 10² kJ
Explanation:
When carbon disulfide, CS₂, forms from its elements, heat is absorbed. The corresponding value for the standard enthalpy of formation of carbon disulfide is 117.36 kJ/mol. The thermochemical equation that represents this process is:
C(graphite) + 2 S(s, rhombic) ⇒ CS₂(g) ΔH°f = 117.36 kJ/mol
117.36 kJ of heat are absorbed when 1 mole of CS₂ is formed. The amount of heat absorbed when 5.0 moles of CS₂ are formed is:
5.0 mol × 117.36 kJ/mol = 5.9 × 10² kJ
