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A 0.885 M solution of KBr whose initial volume is 82.5 mL has more water added until its concentration is 0.500 M. What is the new volume of the solution?

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sebassandin

Answer:

[tex]V_2=146mL[/tex]

Explanation:

Hello there!

In this case, since the equation for the calculation of dilutions is:

[tex]M_1V_1=M_2V_2[/tex]

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

[tex]V_2=\frac{M_1V_1}{M_2}=\frac{0.885M*82.5mL}{0.500M}\\\\V_2=146mL[/tex]

Best regards!

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