(1) The missing numbers are 2 and 5
(2) The missing numbers are 4 and 0
(3) The missing numbers are 6 and 8
(4) The missing numbers are 1 and 9
(5) The missing numbers are 7 and 3
The solution to the given problem is as follows;
In order of mathematical operation, we resolve division first before addition and finally subtraction.
In this problem we are to choose numbers from 0 to 9 and assume that no number will be repeated.
(1) (8 ÷ 2) + (5 - 3) = 6
⇒ 4 + 2 = 6
so the missing numbers are 2 and 5
(2) (4 ÷ 4) + (2 - 0)= 3
⇒ 1 + 2 = 3
so the missing numbers are 4 and 0
(3) (6 ÷ 2) + (6 - 1) = 8
⇒ 3 + 5 = 8
so the missing numbers are 6 and 8
(4) (5 ÷ 1) + (6 - 1) = 9
so the missing numbers are 1 and 9
(5) (0 ÷ 7) + (4 - 3) = 1
so the missing numbers are 7 and 3
Thus, all the numbers from 0 to 9 have been used and non was repeated.
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