Answer:
q = - 2.26 x 10⁻⁶ C
According to answering format:
q = - 2.26
Explanation:
The potential at a distance r from a charge q is given as follows:
[tex]V = \frac{kq}{r}[/tex]
where,
V = Potential = -3680 V
k = Colomb's Constant = 9 x 10⁹ Nm²/C²
r = distance = 5.54 m
Therefore,
[tex]-3680\ V = \frac{(9\ x\ 10^9\ Nm^2/C^2)q}{5.54\ m}\\\\q = \frac{(-3680\ V)(5.54\ m)}{9\ x\ 10^9\ Nm^2/C^2}[/tex]
q = - 2.26 x 10⁻⁶ C
