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If I contain 0.190 moles of gas in a container with a volume of 6.0 liters and at a temperature of 354.0 K, what is the pressure inside the container?

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xCressie

Answer:

0.92 atm

Explanation:

Assuming this is the ideal gas law, PV = nRT. Plug in the values for each.

P = unknown

V = 6.0 L

n = 0.190 moles

R = 0.0821 (there are other rates of constant, such as 8.31, 62.4, but match it up to the correct units! 8.31 will answer in units of kPa and 62.4 will answer in units of mmHg, and lastly 0.0821 answers in atm.)

T = 354.0 K

Set up your equation.

P(6) = 0.190(0.0821)(354)

6p = 5.522046

Divide.

p = 0.920341...

Answer: 0.92 atm

Hope this is right!

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