Respuesta :

oladayoademosu

Answer:

+60 J

Explanation:

Work done by the field on the charge is given by W = qEd where q = charge = +4.0 C, E= electric field strength = 30 N/C and d = distance moved by charge = 0.50 m

So, substituting the values of the variables into the equation, we have

W = qEd

= +4.0 C × 30 N/C × 0.50 m

= +60 Nm

= +60 J

shubhamchouhanvrVT

The work done on the charge will be given by  [tex]W=60\ J[/tex]

What will be the work done on the charge?

It is given that

Charge q= +4C

The distance  D= 0.50 m

Electric field  [tex]E=30 \ \frac{N}{C}[/tex]

Now the work done will be given by

[tex]W= q\times E\times d[/tex]

[tex]W=4\times 30\times 0.5[/tex]

[tex]W=60J[/tex]

Thus the work done on the charge will be given by  [tex]W=60\ J[/tex]

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