How many grams of Carbon Dioxide can be produced by the complete combustion of 140.0 grams of propene; C3H6? If the actual yield turns out to be 200.0 grams of carbon dioxide, what is the percent yield?

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Answer:

2 C3H6 + 9 O2  6 H2O + 6 CO2

Theo. yield is 440.0 g CO2, % yield = 45.45% Explanation: hope it helps here for ur service