The area behind the free throw line on a basketball court is a semicircle with a 6 foot radius. What is the area of the semicircle?

Answer:56.52
let me know if this is wrong
Step-by-step explanation:
A=πr^2 divided by 2
(3.14)(6)^2
(3.14)(36)=113.04
113.04÷2=56.52