Chris is working on a stained-glass project and needs to form a triangle with sides of 8, 12, and 15 inches out of lead cane to enclose the glass. To the nearest tenth of a degree, what is the largest angle he needs to create using the lead caning?

Respuesta :

Answer:

The largest angle needed is [tex]95.1^{o}[/tex].

Step-by-step explanation:

To determine the larges angle as required, let us apply the cosine rule.

[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] - 2ab Cos C

Since in triangles, the longest side is opposite to the largest angle, then;

[tex]15^{2}[/tex] = [tex]8^{2}[/tex] + [tex]12^{2}[/tex] - 2(8 x 12) Cos θ

225 = 64 + 144 - 192 Cos θ

225 = 208 - 192 Cos θ

192 Cos θ = 208 -225

192 Cos θ = -17

Cos θ = [tex]\frac{-17}{192}[/tex]

Cos θ = -0.08854

θ = [tex]Cos^{-1}[/tex] -0.08854

  = 95.07962

θ = [tex]95.1^{o}[/tex]

The largest angle needed is [tex]95.1^{o}[/tex].