Answer:
[tex]Probability = 100\%[/tex]
Explanation:
Given
Crossing of a black chicken and a white chicken
Required
The probability of having erminette chicks
The genotype of a black chicken is represented as: BB
The genotype of a white chicken is represented as: WW
The genotype of an erminette chicken is represented as: BW
Using a Punnett square, we have:
[tex]\begin{array}{ccc}{} & {B} & {B} & {W} & {BW} & {BW} & {W} & {BW} & {BW}\ \end{array}[/tex]
The result of crossing the two chicken gives 4 BW out of a total of 4
i.e 4 erminette chickens out of 4 possible chickens
So, the probability is:
[tex]Probability = \frac{4}{4}[/tex]
[tex]Probability = 1[/tex]
Represent as percentage:
[tex]Probability = 100\%[/tex]
