If y varies jointly as x and z and y = 4 when x = 2 and z = 3, what is y when x = -6 and z = 2?

Answer:
Step-by-step explanation:
Y = kxz
Putting values of y x and z in the equation
4 = k(2)(3)
4 = k6
2/3 = k
Now finding y when x = - 6 and z = 2
Y = kxz
= 2/3(-6)(2)
= - 8