If 10.0 J of work are required to transfer 2.00 coulombs of
charge from point X to point Y in an electric field, what is the
difference in potential between these two points?

Respuesta :

Answer: 5V

Explanation: because 2 goes into 10, five times. Also I know it’s correct cuz I got it right in my quiz

The difference in potential between these two points is 5 V.

Electric potential between the two points

The electric potential between two points is the work done in taking a unit postive charge from one point to another.

The difference in potential between these two points is calculated as follows;

W = qV

V = W/q

V = 10/2

V = 5 V

Thus, the difference in potential between these two points is 5 V.

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