The missing step in the given proof is ∠DEB ≅ ∠ACE
How to prove similar triangles?
From the two triangles named ΔABC and ΔDBE, we can see that in both triangles, the angles ∠ABC and ∠DBE are equal.
Now, we are told that if two parallel lines are cut by a transversal that the corresponding angles formed are congruent. Thus, we can say that ∠DEB and ∠ACE are equal.
Thus, the missing step in the given proof is ∠DEB ≅ ∠ACE.
Read more about Similar Triangles at; https://brainly.com/question/8691470
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