A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature rises to 320K, what is the new volume of the balloon in millimeters?

Respuesta :

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas =  50.0 kPa

[tex]P_2[/tex] = final pressure of gas = 80.0 kPa

[tex]V_1[/tex] = initial volume of gas = 80.0 ml

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = [tex]300K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]320K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}[/tex]

[tex]V_2=53.3ml[/tex]

The new volume is 53.3 ml