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Which equation is y = (x + 3)2 + (x + 4)2 rewritten in vertex form?
y = 2 (x + seven-halves) squared minus one-fourth
y = 2 (x + seven-halves) squared minus one-half
y = 2(x + 7)2 – 73
y = (x + 7)2 – 24

Respuesta :

Lazarbeam13

Answer:

The person above is correct B)y=2(x+7/2)²+1/2

Step-by-step explanation:

varshamittal029

y = 2 (x + seven-halves) squared plus one-fourth equation is y = (x + 3)² + (x + 4)² rewritten in vertex form.

What is vertex form?

If the vertex is (a, b), then the vertex form of an equation can be written as y = p(x-a)² + b, p is a constant.

How to solve this problem?

Here, y = (x + 3)² + (x + 4)²

i.e. y = x² + 6x + 9 + x² + 8x + 16

i.e. y = 2x² + 14x + 25

i.e. y = 2x² + 2*2*(7/2)x + (7/2)² - (7/2)² + 25

i.e. y = 2(x + 7/2)² + 25/2 - 49/4

i.e. y = 2(x + 7/2)² + (50 - 49)/4

i.e. y = 2(x + 7/2)² + 1/4

Therefore, y = 2 (x + seven-halves) squared plus one-fourth equation is y = (x + 3)² + (x + 4)² rewritten in vertex form.

So, no option is correct.

Learn more about vertex form here -

https://brainly.com/question/27614899

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