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The quadratic function f(x) has one zero at x=-5 and a turning point at (3,10). What is the value of its other zero?

Respuesta :

The quadratic function [tex]f(x)[/tex] has one zero at [tex]x=-5[/tex] and a turning point at [tex](3,10)[/tex]. The value of other zero is [tex]11[/tex].

What is Quadratic function?

The Quadratic function [tex]f(x)[/tex] is a polynomial function with one or more variables in which the highest power of the variable is two. i.e.  [tex]f(x) = ax^{2} + bx + c[/tex]

What are zeros?

The zeros of a polynomial [tex]f(x)[/tex] are all the [tex]x[/tex]-values that make the polynomial equals to zero. i.e. [tex]f(x)=0[/tex]

What is turning point?

A turning point is a point at which the derivative changes sign.

We have,

One zero is  [tex](-5)[/tex],

Let other Zero be [tex]"a"[/tex],

Turning point at [tex](3,10)[/tex].

i.e. [tex]x=3[/tex] and [tex]y=10[/tex]

Since the difference between [tex]3[/tex] and [tex](-5)[/tex] is [tex]8[/tex].

So,

The difference between the other zero from [tex]3[/tex] should be the same as the difference between [tex]3[/tex] and [tex](-5)[/tex].

i.e.

[tex]a-3=8[/tex]

[tex]a=11[/tex]

Hence the value of its other zero is [tex]11.[/tex]

To learn more about zeros click here

https://brainly.com/question/5975436

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