Answer:
The initial height of the arrow is 1.5 feet above the ground.
Step-by-step explanation:
Let be the height of the arrow be represented by the function [tex]h(t) = -16\cdot t^{2}+128\cdot t + 1.5[/tex], where [tex]h(t)[/tex] is the current height of the arrow, measured in feet, and [tex]t[/tex], is the time, measured in seconds.
Mathematically speaking, the initial height is the value of [tex]h[/tex] evaluated at [tex]t = 0\,s[/tex]. That is:
[tex]h(0) = -16\cdot (0)^{2}+128\cdot (0) + 1.5[/tex]
[tex]h(0) = 1.5\,ft[/tex]
The initial height of the arrow is 1.5 feet above the ground.