Answer:
F = 144 units
Explanation:
For this exercise we use coulomb's law, for the initial conditions
F₀ = [tex]k \frac{q_1q_2}{r_o^2}[/tex]
indicate that the force F₀ = 36.0 units and the distance is reduced to r = r₀/2 which is the new force
F = [tex]k \frac{ q_1q_2 }{(r_o/2)^2}[/tex]
we substitute
F = 4 [tex]k \frac{q_1q_2}{r_o^2}[/tex]
F = 4 F₀
we calculate
F = 4 36
F = 144 units
