Respuesta :
Answer:
A) F_g = 4.05 10⁻⁴⁷ N, B) F_e = 9.2 10⁻⁸N, C) [tex]\frac{F_e}{F_g}[/tex] = 2.3 10³⁹
Explanation:
A) It is asked to find the force of attraction due to the masses of the particles
Let's use the law of universal attraction
F = [tex]G \frac{m_1m_2}{r^2}[/tex]
let's calculate
F = [tex]6.67 \ 10^{-11} \ \frac{9.1 \ 10^{-31} \ 1.67 \ 10 ^{-27} }{(5 \ 10^{-11})^2 }[/tex]
F_g = 4.05 10⁻⁴⁷ N
B) in this part it is asked to calculate the electric force
Let's use Coulomb's law
F = [tex]k \ \frac{q_1q_2}{r^2}[/tex]
let's calculate
F = [tex]9 \ 10^9 \ \frac{(1.6 \ 10^{-19} )^2}{(5 \ 10^{-11})^2}[/tex]
F_e = 9.2 10⁻⁸N
C) It is asked to find the relationship between these forces
[tex]\frac{F_e}{F_g} = \frac{9.2 \ 10^{-8} }{4.05 \ 10^{-47} }[/tex]
= 2.3 10³⁹
therefore the electric force is much greater than the gravitational force
