Answer:
The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
Explanation:
Given;
potential difference between the plates, V = 10 V
length of each square side of the plates, L = 20 cm = 0.2 m
area of the plates, A = 0.2 x 0.2 = 0.04 m²
separation of the plates, d = 3 cm = 0.03 m
The work done in bringing the plates together is calculated as;
W = ¹/₂qV
[tex]W = \frac{1}{2} (\frac{\epsilon_0 A }{d}V) \times V\\\\W = \frac{\epsilon_0 A V^2}{2d}\\\\W = \frac{8.85 \times 10^{-12} \ \times \ 0.04\ \times \ 10^2}{2(0.03)} \\\\W = 5.9 \times 10^{-10} \ J[/tex]
Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
