Respuesta :

maacastrobr

Answer:

2486 g

Explanation:

First we calculate how many moles of MgBr₂ are required to create such a solution, using the definition of molarity and the given volume and concentration:

  • Molarity = moles / liters
  • 4.5 M = moles / 3.0 L
  • moles = 4.5 M * 3.0 L = 13.5 mol

Now we convert 13.5 moles of MgBr₂ into grams, using its molar mass:

  • 13.5 mol * 184.113 g/mol = 2486 g

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