Answer:
[tex]Q = 29.3^\circ[/tex]
Step-by-step explanation:
Given
[tex]\angle S = 90[/tex]
[tex]RS = 2.2ft[/tex]
[tex]QR = 4.5ft[/tex]
See attachment for ΔQRS
To calculate <Q, we make use of:
[tex]sin\ Q = \frac{Opposite}{Hypotenuse}[/tex]
Where
[tex]Opposite = RS[/tex]
[tex]Hypotenuse = QR[/tex]
[tex]sin\ Q = \frac{RS}{QR}[/tex]
[tex]sin\ Q = \frac{2.2}{4.5}[/tex]
[tex]sin\ Q = 0.4889[/tex]
Take arc sin of both side
[tex]Q = sin^{-1}(0.4889)[/tex]
[tex]Q = 29.3^\circ[/tex]
