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Three squares each have sides of length 6 units and overlap each other as shown below. The points where the sides cross are midpoints. Find the area of the gray figure in square units.

Partition the figure by extending the sides of the ``middle'' square as shown at the right. Each original square contains four $3 \times 3$ small squares. The shaded figure consists of ten $3 \times 3$ squares, so its area is $10 \times 9 = \boxed{90\text{ square

units}}$.

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lhmarianateixeira lhmarianateixeira · Answer 2 · 2022-01-27T14:10:12+01:00

In this exercise we have to use the knowledge of areas to calculate the area of the square in gray, so we have that:

[tex]A=90[/tex]

First it is informed that one side of the square is 6, so every square has exactly:

[tex]l^2=6^2=36[/tex]

Adding that we have 3 squares with the same value of sides:

[tex]36*3=108[/tex]

However, there are areas that are being calculated twice in the central square, these areas are smaller squares that have side values equal to 3, so:

[tex]l^2=3^2=9\\9*2=18\\108-18=90[/tex]

See more about areas at brainly.com/question/1631786

HELP AGAIN!!!!!!!! Three squares each have sides of length 6 units and overlap each other as shown below. The points where the sides cross are midpoints. Find the area of the gray figure in square units.

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HELP AGAIN!!!!!!!!

Three squares each have sides of length 6 units and overlap each other as shown below. The points where the sides cross are midpoints. Find the area of the gray figure in square units.