Answer:
[tex]\frac{3x^2}{(x+2)(x-4)}[/tex]
Step-by-step explanation:
Before adding the fractions we require them to have a common denominator.
Multiply numerator/ denominator of first fraction by x - 4
Multiply numerator/ denominator of second fraction by x + 2
= [tex]\frac{x(x-4)}{(x+2)(x-4)}[/tex] + [tex]\frac{2x(x+2)}{(x+2)(x-4)}[/tex] ← expand and simplify numerators, leaving common denominator
= [tex]\frac{x^2-4x+2x^2+4x}{(x+2)(x-4)}[/tex]
= [tex]\frac{3x^2}{(x+2)(x-4)}[/tex]
