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A car of mass 800 kg goes round a corner of radius 65 m at a
speed of 10 m/s.
a) What size force is needed to achieve this?
b) Suggest how this force is likely to be obtained.
c) What force would be needed if the driver approached the
bend at twice the speed?​

Respuesta :

Lanuel

Answer:

a. Centrifugal force = 1230.77 Newton.

b. Centrifugal force = mv²/r

c. Centrifugal force = 4923.08 Newton.

Explanation:

Given the following data;

Mass = 800kg

Radius = 65m

Velocity = 10m/s

a. To find the force;

Centrifugal force = (800*10²)/65

Centrifugal force = (800*100)/65

Centrifugal force = 80000/65

Centrifugal force = 1230.77 Newton.

b. The force associated with the car is generally referred to as centrifugal force because it's the force required to keep the car in a curved or circular path. It can be calculated using the formula;

Centrifugal force = mv²/r

c. To find the force at twice the speed;

Velocity = 2 * 10 = 20m/s

Centrifugal force = (800*20²)/65

Centrifugal force = (800*400)/65

Centrifugal force = 320000/65

Centrifugal force = 4923.08 Newton.

a. To achieve a car of mass 800 kg goes round a corner of radius 65 m at a            speed of 10 m/s , needed 1230.77 Newton centripetal forces.

b. When an object goes round a corner then centripetal forces keep that object moving in a curved path.

c. When speed is twice. then, 4923.07 Newton centripetal forces needed.

a. Given that car of mass 800 kg goes round a corner of radius 65 m at a

    speed of 10 m/s.

  Centripetal force ,[tex]F=\frac{mv^{2} }{r}[/tex]

  Where m is mass, v is speed of object and r is radius.

   Substituting all values in above equation.

                    [tex]F=\frac{800*10^{2} }{65} =1230.77Newton[/tex]

b. Centripetal force is defined as, the force that is necessary to keep an    object moving in a curved path and that is directed inward toward the center of rotation.

As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion.

c. When speed is twice, then  [tex]v=10*2=20m/s[/tex]

      Centripetal force,[tex]F=\frac{800*20^{2} }{65} =4923.08Newton[/tex]

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