Answer:
a) The distance after 1 minute will be x = 600 m.
b) The distance of vertical drop from A to B is [tex]\Delta y=17658\: m[/tex].
Explanation:
Let's use the parabolic motion equations. Here we have a horizontal initial velocity, and knowing that the horizontal velocity is a constant we have:
a)
[tex]v_{x}=\frac{\Delta x}{\Delta t}[/tex] (1)
Where:
- v(x) is the horizontal velocity (v(x) = 36 km/h = 10 m/s)
- Δx is the displacement
- Δt is the time (Δt = 1 min = 60 s)
Usinf (1) we find Δx:
[tex]\Delta x=v_{x}\Delta t[/tex]
[tex]\Delta x=10*60=600 m[/tex]
Therefore, the distance after 1 minute will be x = 600 m
b)
Here we need to find Δy = y(A)-y(B), this is the distance of vertical drop from A to B.
Using the following equation we will get it:
[tex]y_{B}=y_{A}+v_{iy}t-\frac{1}{2}gt^{2}[/tex]
Let's recall that the initial velocity in the y-direction is 0.
[tex]y_{A}-y_{B}=0t+\frac{1}{2}gt^{2}[/tex]
[tex]\Delta y=\frac{1}{2}gt^{2}[/tex]
[tex]\Delta y=\frac{1}{2}(9.81)(60)^{2}[/tex]
[tex]\Delta y=17658\: m[/tex]
Therefore, the distance of vertical drop from A to B is [tex]\Delta y=17658\: m[/tex].
I hope it helps you!
