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A body of mass m1 = 1.5 kg moving along a directed axis in the positive sense with a velocity
of 11 ms-1 collides head-on with a body of mass m2 = 14 kg moving in the negative sense
with a velocity of 5 ms-1. If the velocity of m1 after the collision is 1 m s-1 in the negative
sense, Apply your scientific knowledge and understanding of collisions to solve the problem
and find the final velocity of m2.

Respuesta :

Answer:

3.71 m/s in the negative direction

Explanation:

From collisions in momentum, we can establish the formula required here which is;

m1•u1 + m2•v2 = m1•v1 + m2•v2

Now, we are given;

m1 = 1.5 kg

m2 = 14 kg

u1 = 11 m/s

v1 = -1 m/s (negative due to the negative direction it is approaching)

u2 = -5 m/s (negative due to the negative direction it is moving)

Thus;

(1.5 × 11) + (14 × -5) = (1.5 × -1) + (14 × v2)

This gives;

16.5 - 70 = -1.5 + 14v2

Rearranging, we have;

16.5 + 1.5 - 70 = 14v2

-52 = 14v2

v2 = - 52/14

v2 = 3.71 m/s in the negative direction

onyebuchinnaji

The final velocity of the body 2 is 3.71 m/s in the negative sense.

The given parameters:

  • Mass of the body 1, m1 = 1.5 kg
  • Mass of the body 2, m2 = 14 kg
  • Initial velocity of body 1, u1 = 11 m/s
  • Initial velocity of the body 2, u2 = - 5m/s
  • Final velocity of body 1, v1 = -1 m/s

The final velocity of the body 2 is calculated by applying the principle of conservation of linear momentum;

[tex]m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\1.5(11) + 14(-5) = 1.5(-1) + 14(v_2)\\\\-53.5 = -1.5+ 14v_2\\\\-52 = 14v_2\\\\v_2 = \frac{-52}{14} \\\\v_2 = -3.71 \ m/s[/tex]

Thus, the final velocity of the body 2 is 3.71 m/s in the negative sense.

Learn more about conservation of momentum here: https://brainly.com/question/7538238

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