Answer:
180feet
Step-by-step explanation:
Given the function that models the height of a ball
s(t) = 144 + 48t − 16t^2.
At maximum height, the velocity is zero ie. ds/dt = 0
ds/dt = 48 - 32t
0 = 48 - 32t
48 = 32t
t = 48/32
t = 1.5secs
Get the maximum height
s(t) = 144 + 48t − 16t^2.
s(1.5) = 144 + 48(1.5)-16(1.5)^2
s()1.5) = 144 + 72 - 16(2.25)
s(1.5) = 144 + 72-36
s(1.5) = 180 feet
Hence the maximum height attained by the ball is 180feet
