Consider the following reaction:
Mg(s) + 2 HCl (aq) → H2(g) + MgCl2(aq)
If 3.65 mol of magnesium and 3.65 mol of hydrochloric acid are reacted, how many
moles of hydrogen gas are produced?

Respuesta :

Answer: 1.825 moles of hydrogen gas are produced.

Explanation:

The balanced chemical equation is:

[tex]Mg(s)+2HCl(aq)\rightarrow H_2(g)+MgCl_2(aq)[/tex]  

According to stoichiometry :

2 moles of [tex]HCl[/tex] require = 1 mole of [tex]Mg[/tex]

Thus 3.65 moles of [tex]HCl[/tex] will require=[tex]\frac{1}{2}\times 3.65=1.825moles[/tex]  of [tex]Mg[/tex]

Thus [tex]HCl[/tex] is the limiting reagent as it limits the formation of product and [tex]Mg[/tex] is the excess reagent.

As 2 moles of [tex]HCl[/tex] give = 1 mole of [tex]H_2[/tex]

Thus 3.65 moles of [tex]HCl[/tex] give =[tex]\frac{1}{2}\times 3.65=1.825moles[/tex]  of [tex]H_2[/tex]

Thus 1.825 moles of hydrogen gas are produced.