Explanation:
When iron rusts in air, iron (III) oxide is produced. How many moles of oxygen react with 12.9 mol of iron in the rusting reaction? 4Fe(s)+3O2(g)→2Fe2O3(s)?
Chemistry The Mole
9.675 mol of oxygen gas.
Explanation:
We have the balanced equation:
4Fe(s)+3O2(g)→2Fe2O3(s)
And so, 4 moles of iron react with 3 moles of oxygen, and therefore, 12.9 mol of iron would react with:
12.9mol Fe⋅3 mol O24mol Fe=9.675 mol O2
