If P is the incenter of triangle JKL, find PJ.

Answer:
PJ = 41.34
Step-by-step explanation:
P is incenter, three angles bisector meet
∠MJP ≅ ∠OJP
PM = PN = PO = 22 (radius: property of incenter)
∠JPM = 90 - ∠MJP = 90 - OJP = ∠JPO
ΔJPM ≅ ΔJPO (ASA) or (SAS)
LM = JO
2x + 3 = 5x - 45
3x = 48
x = 16
JM = 35
PJ = √35²+22² = √1709 = 41.34