hazelbrindle223
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100 BRAINLY POINTS
f(x)=18,000(.88)^x ; x represents the number of years since the car started to depreciate and 18,000 = the initial value of the car. What year will you recieve the car when the car value drops below $2,000? Please do a step by step

Respuesta :

mhanifa

Answer:

  • After 17 years and 3 months

Step-by-step explanation:

Given function:

  • f(x)=18000(0.88)^x

We are looking for the value of x at f(x) < 2000

Solve the equation:

  • 2000 = 18000(0.88)^x
  • (0.88)^x = 2000/18000
  • (0.88)^x = 0.1111
  • log (0.88)^x = log 0.1111
  • x = log 0.1111 / log 0.88
  • x = 17.18

After 17 years and 3 months the car value drops below $2,000

MisterBrainly

Put f(x)=2000 and solve

  • 2000=18000(0.88)^x
  • 2=18(0.88)^x
  • 1/9=(0.88)^x
  • ln(0.111)=xln0.88
  • x=ln(0.111)/ln0.88
  • x=17.18

Atleast 18 years

You will recieve in 18the year going on

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