Answer:
t = 130s
Step-by-step explanation:
[tex]s = 3.9 * 10^{7} km[/tex]
[tex]v = 3 * 10^{5} km/s[/tex]
[tex]t = ?[/tex]
[tex]t = \frac{s}{v}[/tex]
[tex]t = \frac{3.9 * 10^{7} km}{3 * 10^{5}km/s }[/tex]
[tex]t = 130 s[/tex]
If the speed signal sent was actually less, meaning that it would take more time to signal arrives from Earth to Mars. The lower the speed, the higher the time.
