Three vector are oriented as shown in figure below where. A=20.0units, B=40.0units, And C=30.0. (a) The x and Y component of the resultant vector. (b) The magnitude of the resultant vector. (c) Direction of the resultant vector { please help me}

Answer:
Explanation:
a). Vertical component of vector B = Bsin(45)
= 40sin(45°)
= 28.28 units
Horizontal component of vector B = Bcos(45°)
= 40cos(45°)
= 28.28 units
Vertical component of vector C = Csin(45°)
= 30sin(45°)
= 21.21 units
Horizontal component of vector C = Ccos(45°)
= 30cos(45°)
= 21.21 units
Vertical forces = A + Bsin(45°) - Csin(45°)
= 20 + 28.28 - 21.21
= 27.07
Horizontal forces = Bcos(45°) + Ccos(45°)
= 28.28 + 21.21
= 49.49 units
b). Magnitude of resultant force = [tex]\sqrt{(27.07)^2+(49.49)^2}[/tex]
= [tex]\sqrt{3182.045}[/tex]
= 56.41 units
c). Direction of the resultant force → Along vector B (at an angle of 45° from the horizontal line)