Square OPQR is inscribed in triangle ABC. The areas of △AOR, △BOP, △CRQ are 1, 3, and 1, respectively. What is the area of square OPQR?

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thebecks thebecks · Answer 1 · 2021-03-14T16:40:29+01:00

Answer:

9 units²

Step-by-step explanation:

We know that ΔCRQ and ΔBOP are right triangles because RQ and OP are perpendicular to CB.

ΔAOR must also be a right triangle because ∠AOR = ∠OBP and ∠ARO = ∠RCQ.

Because of the Angle-Angle-Angle theorem, we know that ΔAOR ≅ ΔBOP ≅ ΔCRQ.

AR/AO = OP/PB

3(1/2)(AR)(AO) = (1/2)(OP)(PB)

PB = 6, OP = 3

3 x 3 = 9 units²

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andromache andromache · Answer 2 · 2022-03-29T15:06:21+02:00

The area of square OPQR is 9 units².

Since

ΔCRQ and ΔBOP are right triangles since RQ and OP are perpendicular to CB.

Also,

ΔAOR must also be a right triangle due to ∠AOR = ∠OBP and ∠ARO = ∠RCQ.

So it can be like

AR/AO = OP/PB

3(1/2)(AR)(AO) = (1/2)(OP)(PB)

PB = 6, OP = 3

= 3 x 3

= 9 units²

hence, The area of square OPQR is 9 units².

Learn more about area here: https://brainly.com/question/24703634