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How many moles of Al will be consumed when 0.400 mol of Al2O3 are produced in
the following equation?
4A1+302 -> 2A1203
A)
0.200 mol
B) 0.400 mol
C) 0.800 mol
D) 0.600 mol

Respuesta :

maacastrobr

Answer:

C) 0.800 mol

Explanation:

  • 4Al + 3O₂ → 2Al₂O₃

In order to convert from moles of Al₂O₃ into moles of Al, we'll need to use the stoichiometric coefficients, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:

  • 0.400 mol Al₂O₃ * [tex]\frac{4molAl}{2molAl_2O_3}[/tex] = 0.800 mol Al

So the correct answer is option C).

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