y = x2+6x+8 and y = (x+2)(x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of the graph.

Put each of the intercepts in the form of an ordered pair ( . ) ( . ).

You should have three ordered pairs in your answer. Two x-intercepts and one y-intercept. ​

Respuesta :

Answer:

x-int:(-2,0)(-4,0) . y-int:(0,8)

Step-by-step explanation:

y = x2+6x+8 and y = (x+2)(x+4)

x-int:

x+2=0

x= -2

(-2,0)

x-int:

x+4=0

x=-4

(-4,0)

y-int: plug 0 for x

y=(0+2)(0+4)

y=8

(0,8)

The intercepts of a graph are the points where the graph crosses the x or y axes.

  • The x-intercepts are: (-2,0) and (-4,0)
  • The y intercept is (0,8)

Given that:

[tex]y = x^2 + 6x + 8[/tex]

[tex]y = (x + 2)(x + 4)[/tex]

The x-intercepts

This is when [tex]y = 0[/tex]

So, we have:

[tex]y = (x + 2)(x + 4)[/tex]

[tex](x + 2)(x + 4) = 0[/tex]

Split

[tex](x + 2) = 0[/tex] or [tex](x + 4) = 0[/tex]

Solve for x

[tex]x = -2[/tex] or [tex]x = -4[/tex]

Hence, the x-intercepts are: (-2,0) and (-4,0)

The y-intercepts

This is when [tex]x = 0[/tex]

So, we have:

[tex]y = x^2 + 6x + 8[/tex]

Substitute 0 for x

[tex]y = 0^2 + 6 \times 0 + 8[/tex]

[tex]y = 8[/tex]

Hence, the y intercept is (0,8)

Read more about intercepts at:

https://brainly.com/question/1354826

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