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A circuit contains a 20-Ohm resistor and an inductor with an inductance of 0.093 H. If the circuit has a frequency of 60 Hz, what is the total impedance of the circuit?

Respuesta :

Answer:

Explanation:

The computation of the total impedance of the circuit is shown below:

The Total impedance of the circuit is

=

where

X_L^2 = 2πfL

= (2π) (60Hz) (0.093 H)

= 35.06 Omega

Now put the value of X_L^2 in the above formula

=

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