Given:
The probability of landing A is 0.70.
The probability of landing B is 0.60.
The probability of landing both is 0.50.
To find:
The probability of landing A given it lands B.
Solution:
We have,
[tex]P(A) = 0.70[/tex]
[tex]P(B) = 0.60[/tex]
[tex]P(A\cap B) = 0.50[/tex]
The probability of landing A given it lands B is
[tex]P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}[/tex]
[tex]P\left(\dfrac{A}{B}\right)=\dfrac{0.50}{0.60}[/tex]
[tex]P\left(\dfrac{A}{B}\right)=\dfrac{5}{6}[/tex]
[tex]P\left(\dfrac{A}{B}\right)=0.8333...[/tex]
[tex]P\left(\dfrac{A}{B}\right)\approx 0.83[/tex]
Therefore, the probability of landing A given it lands B is about 0.83.
