lolburger lolburger

13-03-2021
Mathematics

contestada

need help pls geometry question

need help pls geometry question class=

Respuesta :

akposevictor akposevictor

18-03-2021

Answer:

55.94°

Step-by-step explanation:

Reference angle = x

Hyp = 25

Adjacent = 14

Apply CAH:

[tex] Cos(x) = \frac{Adj}{Hyp} [/tex]

[tex] Cos(x) = \frac{14}{25} [/tex]

[tex] x = Cos^{-1}(\frac{14}{25}) [/tex]

x = 55.9442023° ≈ 55.94° (to 2 d.p)

Answer Link

Otras preguntas

Holly and Tamar completed the work in the table to determine if a triangle with side lengths of 40, 42, and 58 is a right triangle.

How do you find the vertex of a parabola..?

In fat 12, how many bytes does each directory-entry use to define a file or subdirectory in a directory?

To rousseau, what is the fundamental question that he seeks to address in the social contract?

Number of dispensories in colorado and california

3.5 + 1.2(6.3 -7x) = 9.38

When did hitler comes to power in germany?

Why is speaking to persuade more challenging than speaking to inform?

Which of the following question is written correctly

Classical civilizations greatly influenced the ones that followed. True or False.