Answer:
B. L and N
Step-by-step explanation:
Let's solve each system
✔️System L:
3x + y = 8 => Eqn. 1
x - 4y = -6 => Eqn. 2
x = -6 + 4y
Substitute x = (-6 + 4y) in eqn. 1
3(-6 + 4y) + y = 8
-18 + 12y + y = 8
-18 + 13y = 8
13y = 8 + 18
13y = 26
y = 26/13
y = 2
Substitute y = 2 into Eqn. 2
x - 4y = -6
x - 4(2) = -6
x - 8 = -6
x = -6 + 8
x = 2
Solution to system L = (2, 2)
✔️System M:
4x - 3y = 2 => Eqn. 1
5x - 4y = -30 => Eqn. 2
Multiply eqn 1 by 5, and eqn. 2 by 4
20x - 15y = 10
20x - 16y = -120
Subtract
y = 130
Substitute y = 130 into eqn. 1
4x - 3(130) = 2
4x - 390 = 2
4x = 2 + 390
4x = 392
x = 392/4 = 98
Solution to system M = (98, 130)
✔️System N:
4x - 3y = 2 =>Eqn. 1
2x - 8y = -12 => Eqn. 2
Multiply Eqn. 1 by 2, and eqn. 2 by 4
8x - 6y = 4
8x - 32y = -48
Subtract
26y = 52
y = 52/26
y = 2
Substitute y = 2 into eqn. 1
4x - 3(2) = 2
4x - 6 = 2
4x = 2 + 6
4x = 8
x = 8/4
x = 2
Solution to system N = (2, 2)
