Answer:
[tex]V_2=2.5m^3[/tex]
Explanation:
Hello!
In this case, according to the Charles' law as a directly proportional relationship between volume and temperature:
[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]
Thus, in order to compute the final volume, V2, we obtain the following expression:
[tex]V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5m^3*300K}{600K}\\\\V_2=2.5m^3[/tex]
Best regards!
